Balanced load power
- Input
- VLL = 400 V, I = 10 A, PF = 0.9
- Method
- Use S = sqrt(3)VLLI/1000 and P = S*PF.
- Formula
- P = 1.732*400*10*0.9/1000
- Intermediate steps
- S = 6.928 kVA
- P = 6.235 kW
- Final result
- 6.24 kW
- Interpretation
- The balanced load is about 6.24 kW.
- Limitation
- Unbalanced phase currents are not represented.